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Custom function (maloma function) #numberblocks #numberblock #maloma #function #custom #number
Heres a formula if you want to know N*((n*2)*n)+n=n Like this: 1*(2*1)+1=3 2*(4*2)+2=18 3*(6*3)+3=57 4*(8*4)+4=132 5*(10*5)+5=255 6*(12*6)+6=438 7*(14*7)+7=693 8*(16*8)+8=1,032 9*(18*9)+9=1,467 10*(20*10)+10=2,010 If you found it simply divided by three or n divide to get a perfect maloma number (because all of them are divided by three and they are guaranteed to be a non-decimal number)like this 3/3=1 18/3=6 57/3=19 132/3=44 255/3=85 438/3=146 693/3=231 1032/3=344 1467/3=489 2010/3=670 N-divide 3/1=3 18/2=9 57/3=19 132/4=33 255/5=51 438/6=73 693/7=99 1032/8=129 1467/9=163 2010/10=201 Here a shorter maloma method: 2(n)^3+n
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