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slightly higher quality math test because apparently y'all are making these | #math #test #cringe #why #imboredsoimadethis
amended 27/12 because there are too many mistakes, made this as a joke
fire1Reply
Certainly, let's solve the summation problem: Problem: Solve the summation: āˆ‘_(n=1)^5 (C_(5,n) * i^n) Solution: Step 1: Understanding the summation: * The summation symbol (āˆ‘) indicates that we need to add up a series of terms. * The index variable is n, which starts at 1 and goes up to 5. * Inside the summation, we have two parts: * C_(5,n): This represents the binomial coefficient (also known as "5 choose n"). It is the number of ways to choose n items from a set of 5 items. * i^n: This is the complex number i raised to the power of n. Step 2: Calculating the terms: Let's calculate each term of the summation for n from 1 to 5: * n = 1: C_(5,1) * i^1 = 5i * n = 2: C_(5,2) * i^2 = 10i^2 * n = 3: C_(5,3) * i^3 = 10i^3 * n = 4: C_(5,4) * i^4 = 5i^4 * n = 5: C_(5,5) * i^5 = i^5 Step 3: Adding the terms: Now we add up all the terms: 5i + 10i^2 + 10i^3 + 5i^4 + i^5 Step 4: Simplifying the expression: * Recall that i^2 = -1, i^3 = -i, and i^4 = 1. * Substitute these values
fire1Reply
only if i was a variable..
fire1Reply
don't even bother doing this
fire1Reply
Don't solve me the 5th question anyways
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AE Summation of
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